Physics High School
Answers
Answer 1
The water present in the middle doesn't experience pressure as much as that experienced by water at the bottom. Pressure is more at bottom surface hence fluids flow from higher pressure to lower pressure. This is why the water rushes out from the bottom hole much faster than from the upper hole
Related Questions
A light-year is a unit of measurement that would most appropriately be used to measure which distance?
a. Between two galaxies b. Between Earth and Jupiter c. Between Earth and the sun d. Between the moon and Earth
Answers
A light-year is a unit of measurement which is used to measure distance between the Earth and the sun.
What is Light year?
This is defined as the distance light travels in the time it takes the Earth to orbit the Sun.
It is also the distance a beam of light travels in a single earth year which is why option C was chosen as the most appropriate choice.
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13. A mass of 1 kg undergoes simple harmonic motion with amplitude of 1 m. If the period of the oscillation is 1 s, calculate the internal energy of the system.
Please show all of your work.
Answers
first we need omega
T=1s
Hence
[tex]\\ \rm\rightarrowtail \omega=\dfrac{2\pi}{T}=2\pi[/tex]
Now
Total energy:-
[tex]\\ \rm\rightarrowtail \dfrac{1}{2}m\omega ^2A^2[/tex]
[tex]\\ \rm\rightarrowtail \dfrac{1}{2}(1)(2\pi)^2(1)^2[/tex]
[tex]\\ \rm\rightarrowtail \dfrac{1}{2}(4\pi ^2[/tex]
[tex]\\ \rm\rightarrowtail 2\pi ^2[/tex]
[tex]\\ \rm\rightarrowtail 2(3.14)^2[/tex]
[tex]\\ \rm\rightarrowtail 19.72J[/tex]
a 600kg wrecking ball is swinging from a crane as shown. When the wrecking ball reached the bottom of the path, the wrecking ball is moving 10m/s
Answers
Answer:
Explanation:
The picture is cut off so the wrecking ball and its path are not shown. It would be better if the whole picture is available.
Based on the written info, at the bottom of the path, the wrecking ball is moving at 10m/s.
The centripetal acceleration = velocity^2 / radius
= 10^2 / 25
= 100 / 25
= 4m/s^2
The centripetal force = mass * centripetal acceleration
= 600*4
= 2400N
As the ball is moving horizontally at the bottom, net vertical force is zero.
So Tension force in cable = Wrecking ball weight + Centripetal force
= 600*g + 2400
= 6000 + 2400; assuming g is 10m/s^2
= 8400N
Conduction is greater in solids .explain in your own words Why?
Answers
Explanation:
because conduction takes place in objects whose particles are close/touching each other therefore conduction happens in solid as liquid and gas paricles are not close to each other
4. Which best explains the function of the alveoli in the respiratory system?
Page 135
A. The alveoli help to keep the lungs healthy by providing a way for all the cells
in the lungs to obtain nutrients from the bloodstream
B. The alveoli help to keep the lungs inflated when you breathe out and make it
possible to absorb oxygen
C. The alveoli provide a large surface area for absorbing oxygen from the air and
releasing carbon dioxide wastes from the bloodstream
D. The alveoli provide a large surface area for absorbing oxygen from the air
when you breathe in and look like a bunch of grapes
a
Answers
Answer:
C
Explanation:
Alveoli are tiny functioning structures that compose your lungs. They help with respiration. They have a large total surface area, which is very useful for respiration. The more surface area there is, the more transactions can happen. Which means that breathing will be easier/faster when you have more alveoli. (Please rate this answer if you have time!)
if predators and habitat do not change, which shade of frogs will have the greatest fitness
Answers
Answer:
The dark green frogs will
Explanation:
because they blend more within the night than any other frog or animal out there
I hope this helps
If predators and habitat do not change, the dark green frogs will have the greatest fitness.
What is predators?
Predators are organisms that hunt and kill other organisms for food. The organisms that are consumed by the predators are known as the prey.
The dark green frogs will have greatest fitness because they blend more within the night than any other frog or animal out there.
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A stationary siren on a firehouse is blaring at 81Hz. Assume the speed of sound to be 343m/s. What is the frequency perceived by a firefighter racing toward the station at 11km/h
Answers
For a stationary siren on a firehouse is blaring at 81Hz. Assume the speed of sound to be 343m/s, the frequency perceived is mathematically given as'
F=81.721Hz
What is the frequency perceived by a firefighter racing toward the station at 11km/h?
Generally, the equation for the doppler effect is mathematically given as
[tex]F'=\frac{vs+v}{vs}*f[/tex]
Therefore
F=81(343+3.05556)/343
F=81.721Hz
In conclusion, the frequency is
F=81.721Hz
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Is distance a vector quantity
Answers
Explanation:
Nope, displacement is a vector quantity, whereas distance is the scalar (magnitude) of the total displacement.
Hope this clears things up :))
What is the speed of a wave that has a frequency of 173 Hz and a wavelength of 2. 59 meters? Express your answer to the nearest whole number. M/s.
Answers
The speed of the wave will be v= 448.07 m/s
What is speed of the wave?
The speed of the wave is defined as the distance traveled by the wave with respect to the time.
The frequency is defined as the number of cycles per seconds it is calculated in hertz
The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
Now frequency = 173 hertz
wavelength = 2.59 m
The velocity will be given by the formula:
[tex]v=\lambda\times f[/tex]
[tex]v=173\times 2.59=488.07 \ \frac{m}{s}[/tex]
Thus the speed of the wave will be v= 448.07 m/s
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15. A 0.500-kg mass suspended from a spring oscillates with a period of 1.50 s. How much mass must be added to the object to change the period to 2.00 s?
The answer is 0.389 kg but please show your work.
Answers
Let's look at relationship
[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{m}{k}}[/tex]
[tex]\\ \rm\rightarrowtail T\propto \sqrt{m}[/tex]
Hence
[tex]\\ \rm\rightarrowtail \dfrac{T_1}{T_2}=\sqrt{\dfrac{m1}{m2}}[/tex]
[tex]\\ \rm\rightarrowtail \dfrac{1.5}{2}=\sqrt{\dfrac{0.5}{m2}}[/tex]
[tex]\\ \rm\rightarrowtail 0.75^2=\dfrac{0.5}{m2}[/tex]
[tex]\\ \rm\rightarrowtail m_2=\dfrac{0.5}{0.75^2}[/tex]
[tex]\\ \rm\rightarrowtail m_2=0.889[/tex]
Hence
Mass needs to added =0.889-0.500=0.389kg
Answer
Mass needs to added =0.889-0.500=0.389kg
Explanation:
A thin uniform disk of mass m and radius r has a string wrapped
Answers
The magnitude of the weight of the disk is greater than the magnitude of the tension force of the string. ((c) [tex]F_{T} < F_{g}[/tex])
How to analysis a rigid body on dynamical condition
A rigid body is a system whose geometry cannot be neglected and in which deformations due to external forces applied on the system are negligible.
In this question we need to establish a free body diagram with all critical forces and motion conditions. There are two external forces: (i) tension ([tex]F_{T}[/tex]), (ii) weight ([tex]F_{g}[/tex]), both in newtons.
The disk falls due to gravity and rotates around the string in a case of rolling, which combines rotation and translation. By Newton's laws of motion we have the following expression:
[tex]\sum F = -F_{g}+F_{T} = -m\cdot R\cdot \alpha[/tex] (1)
Where:
[tex]m[/tex] - Mass of the disk, in kilograms.[tex]\alpha[/tex] - Angular acceleration, in radians per square second.
By algebra we derive the following relationship between the two forces:
[tex]-F_{g} = -F_{T}-m\cdot R\cdot \alpha[/tex]
[tex]F_{g} > F_{T}[/tex]
Therefore, the magnitude of the weight of the disk is greater than the magnitude of the tension force of the string. ((c) [tex]F_{T} < F_{g}[/tex]) [tex]\blacksquare[/tex]
Remark
The statement is incomplete and poorly formatted. Correct and complete form is shown below:
A thin uniform disk of mass m and radius r has a string wrapped around its edge and attached to the ceiling. The bottom of the disk is at height 3R above the floor, as shown above. The disk is released from rest. The rotational inertia of a disk around its center is [tex]I = \frac{1}{2}\cdot M\cdot R^{2}[/tex].
When released from rest, the disk falls and the string unwinds. The force that the string exerts on the disk is [tex]F_{T}[/tex], and the gravitational force exerted on the disk is [tex]F_{g}[/tex]. Which of the following expression correctly relates [tex]F_{T}[/tex] and [tex]F_{g}[/tex] as the disk falls?
(a) [tex]F_{T} > F_{g}[/tex], (b) [tex]F_{T} = F_{g}[/tex], (c) [tex]F_{T} < F_{g}[/tex]
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A brass ring of diameter 10. 00 cm at 14. 3°c is heated and slipped over an aluminum rod of diameter 10. 01 cm at 14. 3°c. Assume the average coefficients of linear expansion are constant
Answers
The coefficients js sis sided Iskenderun Diane Edison sn
Temperature for combination be cooled to separate the brass ring of diameter 10.00 cm at 14.3°c and an aluminum rod of diameter 10.01 cm at 14.3°c is -204.7° C, which is not attainable.
What is linear expansion?
The linear expansion is the expansions of metal when they are heated and their length is changed along one direction.
A brass ring of diameter 10. 00 cm at 14. 3°c is heated and slipped over an aluminum rod of diameter 10. 01 cm at 14. 3°c. Assume the average coefficients of linear expansion are constant
(a) To what temperature must the combination be cooled to separate the two metals?
To find the temperature, use the following formula,
[tex]T=T_o+\dfrac{d_o^A-d_o^B}{\alpha _Ad_o^A-\alpha _Ad_o^B}[/tex]
Put the values,
[tex]T=14.3+\dfrac{10.01-10}{(19\times10^{-6})(10.01)-(24\times10^{-6})(10)}\\T=-204.7^o C[/tex]
Thus, temperature for combination be cooled to separate the brass ring of diameter 10.00 cm at 14.3°c and an aluminum rod of diameter 10.01 cm at 14.3°c is -204.7° C, which is not attainable.
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A 10. 0 cm object is 5. 0 cm from a concave mirror that has a focal length of 12 cm. What is the distance between the image and the mirror? 3. 5 cm –3. 5 cm 8. 6 cm –8. 6 cm.
Answers
The distance between the image and the mirror is -8.6 cm
What is concave mirror?
A concave mirror has a reflective surface that is curved inward and away from the light source. Concave mirrors reflect light inward to one focal point.
Unlike convex mirrors, the image formed by a concave mirror shows different image types depending on the distance between the object and the mirror.
Let's use the mirror equation to solve the problem:
[tex]\dfrac{1}{f}=\dfrac{1}{d_o}+\dfrac{1}{d_i}[/tex]
where f is the focal length of the mirror, the distance of the object from the mirror, and the distance of the image from the mirror.
For a concave mirror, for the sign convention f is considered to be positive. So we can solve the equation for by using the numbers given in the text of the problem:
[tex]\dfrac{1}{12}=\dfrac{1}{5}+\dfrac{1}{d_i}[/tex]
[tex]\dfrac{1}{d_i}=-\dfrac{7}{60}[/tex]
[tex]d_i=-8.6\ cm[/tex]
Where the negative sign means that the image is virtual, so it is located behind the mirror, at 8.6 cm from the center of the mirror.
Hence the distance between the image and the mirror is -8.6 cm
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Money functions primarily as a medium of
a unit of
and a store of value.
.
Answers
Answer:
buying and selling goods and services. and exchange account
Explanation:
:)
Answer:
when money is used to intermediate the exchange of goods and services
What best describes the motion of the medium particles in a longitudinal wave? The medium does not move. The medium moves in all directions. The medium vibrates as it moves in a circular path around the wave. The medium vibrates parallel to the direction of the wave.
Answers
In the motion of the medium particles in a longitudinal wave, the medium vibrates parallel to the direction of the wave.
What is a longitudinal wave?
A longitudinal wave is a wave that is transversing along the length. When the displacement of medium and travel of wave is the same in that condition wave is known as the longitudinal wave.
It requires some medium to travel. A mechanical and sound wave is an example of a longitudinal wave.
Hence in the motion of the medium particles in a longitudinal wave, the medium vibrates parallel to the direction of the wave.
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Answer:
d the medium vibrates parallel to the direction of the wave.
Explanation:
Two planets are orbiting a star in a distant galaxy the first has a semimajor axis of 150 x 10^6 km an eccentricity of 0. 20 and a period of 1. 0 earth years
Answers
For two planets orbiting a star in a distant galaxy, having the first semimajor axis of 150 x 10^6 km, the period of the second plane is mathematically given as
T=2.2earth year
What is the period of the second planet?
Generally, the equation for the time period is mathematically given as
[tex]T^{2} \appox a^{3}[/tex]
Therefore, for planet one
[tex]1^2\approx (150 x 10^6)^3[/tex]
In conclusion, For planet 2
T^2=(250/150)^3
T=√4.632
T=2.2earth year
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The period of the second planet for two planets circling a star in a faraway galaxy with a first semimajor axis of 150× 10⁶ km. The time period of the planet will be 2.2 earth years.
What is the time period of the revolution?
The time period of the revolution is the time required to complete one revolution. It is guven by T. It is measured in seconds.
The equation of the time period is found as;
[tex]\rm T = \frac{250}{150} ^3 \\\\ T= \sqrt{4.632} \\\\ T=2.2 \ earth \ year[/tex]
Hence the time period of the planet will be 2.2 earth years.
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The presence of which magnetic feature best explains why a magnet can act at a distance on other magnets or on objects containing certain metals? fields dipoles domains forces
Answers
The orientation with the largest magnetic torque on the dipole is Orientation B (See attached image).
What is Magnetic Torque?
The torque on the dipole is defined as:
τ = µ×B,
where B is the external magnetic field.
The magnitude of this torque is µB sinθ, where θ is the angle between B and µ
Magnetic Torque is highest when;
→ →
µ ⊥ β
That is when θ = 90°. Hence B is the correct answer. Please see attached image.
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Answer:
b
Explanation:
(a) before the submarines pass each other, sub b quickly turns around and speeds up to 12. 4 m/s. What is the change in frequency noticed by observers on sub b? (enter you answer to one decimal place. )
Answers
The change in frequency noticed by observers on sub b is : 2.66 Hz before the submarines pass each other.
Given data:
New speed of Sub b ( Vb ) = 12.4 m/s
F₁ = 1416.44 Hz
Frequency of sonar wave ( Fₐ ) = 1400 Hz
Speed of sound in water ( V ) = 1533 m/s
Speed of submarine A ( Va ) = 8.4 m/s
Determine the change in frequency observed on sub B
The change in frequency can be calculated using the formula below
F₁' = Fₐ ( V + Vb / V - Vₐ )
= 1400 ( 1533 + 12.4 / 1533 - 8.4 )
= 1400 ( 1545.4 / 1524.6 )
= 1419.1 Hz
Final step : determine the change in frequency
ΔF = F₁' - F₁
= 1419.1 - 1416.44
= 2.66 Hz.
Hence we can conclude that The change in frequency noticed by observers on sub b is : 2.66 Hz.
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The frequency is the number of waves that travel through a particular place in one unit of time. The change in frequency noticed by observers on sub b is 2.66 Hz.
What is the frequency?
The frequency is the number of waves that travel through a particular place in one unit of time. It may also be described as the number of cycles or vibrations experienced by a body in periodic motion in one unit of time.
Given that the new speed of the sub B is 12.4 m//sec, while the frequency of the submarine is 1416.44 Hz. The frequency of the sonar wave of submarine A is 1400 Hz. Also, the speed of sound in water, V is 1533 m/sec, and the speed of submarine A is 8.4 m/s.
Now, the frequency of the sub B after the speed is increased will be equal to,
[tex]F_1' = F_a \times \dfrac{(V+V_b)}{(V-V_a)}[/tex]
[tex]\rm = 1400 \times \dfrac{(1533+12.4)}{(1533-8.4)}\\\\=1400 \times \dfrac{1545.4}{1524.6}\\\\=1419.1\ Hz[/tex]
Further, the change in frequency noticed by observers on sub b,
[tex]\rm \triangle F = F_1'-F_1 = 1419.1-1416.44 = 2.66\ Hz[/tex]
Hence, the change in frequency noticed by observers on sub b is 2.66 Hz.
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a woman weighs 580 N . what is her mass?
Answers
Answer:
Themassof woman is59.18 kg.Given data:Weight of women is,.An object on the surface has itsweightsuch that it is determined by theforce of gravityacting on the object. Mathematically, the weight of object is calculated bymultiplyingthegravitational accelerationwith mass of object.Then,Here,mis themassof woman andgis thegravitational acceleration.Solving as,Thus, themassof woman is59.18 kg.
Explanation:
59.18 kg
Hope this helps! :)
A proton wit a kinetic energy of 9. 3 x 10^-15 j moves perpendicular to a magnetic field of 0. 87 t. What is the radius of its circular path?
Answers
The radius of the given circular path moved by the proton which is perpendicular to a magnetic field of 0.87 T determined as 4 cm.
Magnetic force of the proton
The magnitude of the magnetic force on the proton is determined using the following formula;
F = qvBsin(θ)
Centripetal force on the proton
The centripetal force of the circular path is given as;
F = mv²/r
Solve the two equations together,
[tex]\frac{mv^2}{r} = qvBsin(90)\\\\r = \frac{mv}{qB}[/tex]
Where;
v is the speed of the protonSpeed of the proton
The speed of the proton is determined from its kinetic energy;
[tex]K.E = \frac{1}{2}mv^2\\\\ v= \sqrt{\frac{2K.E}{m} } \\\\v = \sqrt{\frac{2 \times 9.3 \times 10^{-15}}{1.67 \times 10^{-27}} } \\\\v = 3.33\times 10^6 \ m/s[/tex]
Radius of the circular path
The radius of the circular path is calculated as follows;
[tex]r = \frac{(1.67 \times 10^{-27}) \times (3.33 \times 10^6)}{(1.6\times 10^{-19}) \times (0.87)} \\\\r = 0.04\ m\\\\r = 4 \ cm[/tex]
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Two pistons are in an enclosed volume with fluid in between them, such that
movement in one piston affects the location of the other piston, as shown in
the image below. If an explosion occurs in the piston on the left such that it
moves 1 m, what is the distance that the piston on the right will move
(assuming that friction can be neglected)? (Recall that work on an object is
equal to the force on the object times the distance it is moved, and that work
is conserved.)
Cross-sectional area - 25 mm
Cross-sectional area = 0,5 m
A. 2 m
B. 0.5 m
C. 1 m
D. 0.25 m
Answers
Answer:
The pressure in the fluid just below Piston 1 is
p_1=F_1/A_1=361\text{ Pa}.p
1
=F
1
/A
1
=361 Pa.
The pressure in the fluid just below Piston 2 is the same according to Pascal's law:
p_2=p_1=361\text{ Pa}.p
2
=p
1
=361 Pa.
The force being exerted on Piston 2 to keep the two pistons in equilibrium is
F_2=p_2A_2=330\text{ N}.F
2
=p
2
A
2
=330 N.
Explanation:
Brody drives 180 km in two hours. How fast is he travelling?
should be in km/hour)
Answers
Answer:
90 km/h
Explanation:
we just divide the distance by the time to get the speed.
At a construction site, a crane lifts an object to a certain height in 12 seconds, and a second crane does the same work in 6 seconds. Compared to the power developed by the first crane, the power developed by the second crane is which of the following?
A. The same
B. One-half as much
C. Twice as much
D. Four times as much
Answers
option C
hope it helps...!!!
The parenting style that can be described as restrictive and controlling is called __________. a. authoritarian b. permissive c. neglectful d. authoritative please select the best answer from the choices provided a b c d
Answers
The parenting style that can be described as restrictive and controlling is called authoritarian.
What is authoritarian?
The rejection of political plurality, the use of strong central power to maintain the political status quo, and reductions in the rule of law,
The separation of powers and democratic voting characterize authoritarianism.
Many typologies of authoritarian systems of administration have been developed by political scientists.
Authoritarian governments can be autocratic or oligarchic, and they can be founded on party or military authority.
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What is the 3rd largest planet in the solar system?
Answers
Answer:
Uranus
Explanation:
Your welcome
A planet is a celestial body. The third-largest planet in the solar system is Uranus.
What is a planet?
A celestial body is differentiated from the fixed stars by its apparent mobility (including the moon and sun), especially in relation to its claimed impact on people and events.
A planet is a celestial body. The third-largest planet in the solar system is Uranus.
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A current in a wire increases from 2 a to 6 a. how will the magnetic field 0.01 m from the wire change? it increases to four times its original value. it increases to three times its original value. it decreases to one-fourth its original value. it decreases to one-third its original value.
Answers
Answer:
It increases to three times it's original value.
Explanation:
B
Hi there!
Recall the equation for the magnetic field of a wire (assuming infinite):
[tex]B = \frac{\mu _0 i_{encl}}{2\pi r}[/tex]
B = Magnetic field (T)
μ₀ = Permeability of Free Space (Tm/A)
i = enclosed current (A)
r = distance from wire (m)
From the equation, we can see that there is a DIRECT relationship between the current and the magnetic field.
Therefore, if the current is increased by a factor of 3, the FIELD will also be increased by a factor of three.
If a train going 60 m/s hits the brakes, and it takes the train 85 seconds to stop, what is
the train's acceleration?
Answers
Question :-
If a Train going with 60 m/s Speed hits the Brakes, and takes 85 sec to stop. What is the Acceleration of the Train ?
Answer :-
Acceleration of Train is 0.70 m/s² .
Explanation :-
As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .
For calculating the Acceleration , we will use the Formula :-
[tex] \bigstar \: \: \: \boxed { \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \\ [/tex]
Where ,
V denotes to Final Velocity .U denotes to Initial Velocity .T denotes to Time Taken .
Therefore , by Substituting the given values in the above Formula :-
[tex] \dag \: \: \: \: \sf{Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \\ [/tex]
[tex] \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{0 \: - \: 60}{85} } \\ [/tex]
[tex] \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{60}{85} } \\ [/tex]
[tex] \longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 0.70 }} [/tex]
Hence :-
Acceleration = 0.70 m/s² .
[tex] \underline {\rule {210pt} {4pt}} [/tex]
Note :-
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Answer:
Question :-
If a Train going with 60 m/s Speed hits the Brakes, and takes 85 sec to stop. What is the Acceleration of the Train ?
Answer :-
Acceleration of Train is 0.70 m/s² .
Explanation :-
As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .
For calculating the Acceleration , we will use the Formula :-
\begin{gathered} \bigstar \: \: \: \boxed { \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \\ \end{gathered}
★
Acceleration=
t
v−u
Where ,
V denotes to Final Velocity .
U denotes to Initial Velocity .
T denotes to Time Taken .
Therefore , by Substituting the given values in the above Formula :-
\begin{gathered} \dag \: \: \: \: \sf{Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \\ \end{gathered}
†Acceleration=
Time
FinalVelocity−InitialVelocity
\begin{gathered} \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{0 \: - \: 60}{85} } \\ \end{gathered}
⟼Acceleration=
85
0−60
\begin{gathered} \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{60}{85} } \\ \end{gathered}
⟼Acceleration=
85
60
\longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 0.70 }}⟼Acceleration = 0.70
Hence :-
Acceleration = 0.70 m/s² .
\underline {\rule {210pt} {4pt}}
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Define resistance of a conductor. State the factors on which resistance of a conductor depends.
Name the device which is often used to change the resistance without changing the voltage source in an electric circuit.
Calculate the resistance of 50 m length of wire of cross-sectional area 0.01 square mm and of resistivity 5 ×10 ^-8 ohm m
Answers
Answer:
1. Resistance is the opposition offered in a path of flow of current by the atoms or molecules of the conductor.
Factors on which resistance of a conductor depends are:
Length [tex]R \propto l[/tex]
Area of cross section [tex]R \propto \dfrac{1}{A}[/tex]
Nature of the material
2. Rheostat is used to change the resistance without changing the voltage source in an electric circuit.
3.
Given :
[tex]\dashrightarrow l = 50 m[/tex]
[tex]\dashrightarrow A = 0.01 {mm}^{2} [/tex]
[tex]\dashrightarrow A = 0.01 \times {10}^{ - 6} \: {m}^{2} [/tex]
[tex]\dashrightarrow \rho = 5 \times {10}^{ - 8} \: \Omega \: m[/tex]
We know that,
[tex] \dashrightarrow R = \rho \dfrac{l}{A}[/tex]
[tex] \dashrightarrow R = 5 \times {10}^{ - 8} \bigg(\dfrac{50}{0.01 \times {10}^{ - 6} } \bigg)[/tex]
[tex] \dashrightarrow { \pink{ \underline{ R = 250 \: \Omega }}}[/tex]
The resistance of a conductor is the opposition to the flow of current and depends on the length and area of the material
What is resistance of a conductor?
Resistance is the opposition to the flow of current by the atoms or molecules of the conductor.
The factors on which resistance of a conductor depends are:
Length of materialcross-sectional area of the materialNature of the material
A Rheostat is the device used to change the resistance without changing the voltage source in an electric circuit.
The resistanceis given as:
R = resistivity × length/ area
Area = 0.01 square mm = 1.0 × 10^-8 square m
R = (50 × 5 ×10 ^-8 ohm m)/1.0 × 10^-8 square m
Resistance = 250 ohm
Therefore, resistance of a conductor is the opposition to the flow of current.
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Light travels at 3.0 × 108 m/s in a vacuum. use the index of refraction for water to determine the speed of light in water. round your answer to the nearest tenth. × 108 m/s
Answers
Answer:
the answer is 2.3. I just answered this question and got it right.
Explanation:
The phenomenon bending of a wave as it crosses from one medium to another is said to be refraction. The speeds of light in the water will be 2.25×10⁸ m/sec.
What is the definition of refraction?
The phenomenon bending of a wave as it crosses from one medium to another is said to be refraction. The difference in density is the cause of the bending.
Refraction is a term that is used to describe the phenomenon of refraction."The change in direction of a wave traveling through one medium to another is known as refraction."
The following data are given in the problem;
C is the Speed of light in a vacuum =3×10⁸ m/sec.
n is an index of refraction for water = 1.333
v is the speed of light in the water=?
The index of refraction is the ratio of the speed of light in a vacuum to the speed of light in water. By the formula of the index of refraction.
[tex]n=\dfrac{c}{v}[/tex]
[tex]V=\dfrac{c}{n}[/tex]
[tex]V=\dfrac{3\times10^8}{1.333}[/tex]
[tex]V=2.25\times 10^8 m/s[/tex]
Hence the speed of light in the water will be 2.25×10⁸ m/sec.
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One square megameter is equal to 1. 0×106 square kilometers. How many square megameters are in 4,000,000 square kilometers?
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Answer:
One has 1E6 km^2 / MM
4E6 km^2 / (1E6 km^2/MM) = 4 MM or 4 megameter
In 4000,000 square kilometers, there are 4 square megameters if the one square megameter is equal to 1. 0×106 square kilometers.
What is unit conversion?
It is defined as the conversion from one quantity unit to another quantity unit followed by the process of division, and multiplication by a conversion factor.
We have:
One square megameter = [tex]1\times10^6[/tex]
Let's suppose the x square megameters in the 4,000,000 square kilometers
Then x can be found as follows:
[tex]\rm x = \frac{4,000,000}{1\times10^6}[/tex]
x = 4 square megamters
Thus, in 4000,000 square kilometers, there are 4 square megameters if the one square megameter is equal to 1. 0×106 square kilometers.
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